A 3.0-m-long uniform rod with a mass of 12 kg rotates about an axis through its center. There are two applied forces as shown in the diagram below.

The moment of inertia for a rod rotating about its center is given by I = 1/12 M L^2.

-Assuming a counterclockwise rotation is positive, calculate the net torque on the rod.

-Calculate the moment of inertia of the rod.

-Calculate the angular acceleration of the rod.

-If the rod accelerates from rest, determine the time it takes the rod to rotate through a 90° angle.

-How many revolutions does the rod make in 5.0 s?